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GKRECALL bring you the complete and important daily  Quant Quiz to achieve more marks in Banking, Insurance, UPSC, SSC, CLAT, Railways and all other competitive Exams. We prepare it based on our daily current affairs.Hope you like it.

START QUIZ

ARITHMETIC SUM

1.A container contains 165 litres of milk. Some quantity of milk is taken out and water equal to half of that quantity of milk is added in the container. Now ratio of milk to water in the container becomes 5:3. What is the quantity of water added in it?
40 litre
45 litre
60 litre
30 litre
90 litre

2.Two boxes contain 4 and 16 balls respectively. Two balls in the first box and four in the second, are black. If a box is chosen randomly and two balls are drawn at random from it, what is the probability that at least one ball is black if the ball is not replaced?
11/20
43/120
77/120
9/20
None of these

3.Train A, travelling at 84 kmph, overtook train B, traveling in the same direction, in 10 seconds. If train B had been traveling at twice its speed, then train A would have taken 22.5 seconds to overtake it. Find the length of train B, given that it is half the length of train A.
180 m
100 m
200 m
150 m
50 m

4.A solid sphere of radius 6 cm is melted and re-casted into a hollow cylinder of uniform thickness. If the external radius of the base of the cylinder is 5 cm and its height is 32 cm, find the uniform thickness of the cylinder ?
3 cm
1.5 cm
1 cm
2.5 cm
None of these

5.X and Y entered into partnership with Rs. 700 and Rs. 600 respectively. After another 3 months, X withdrew two-sevenths of his stock but after 3 months, he puts back three-fifths of what he had withdrawn. The total profit at the end of the year is Rs. 726. How much money should X receive?
Rs. 336
Rs. 366
Rs. 633
Rs. 663
None of these

6.Cost price of a pen is Rs. 50 and that of notebook is Rs. 140. If pen is sold at 200% profit, then in order to purchase 10 such note books how many pens are required to sell if only profit money is used to buy notebooks?
14
18
15
20
16

7.Length of two trains are 150 m and 200 m respectively and the ratio (shorter: longer) of their speed is 2 : 5. If they cross each other in opposite direction in 15 second then in what time faster train will overtake the slower train.
20 seconds
25 seconds
32 seconds
35 seconds
27 seconds

8.If length of a rectangle is decreased by 6 cm we get a square and the area of square formed is 252 cm² less than the area of square formed when breadth of the original rectangle is increased by 6 cm. Find the perimeter of the rectangle.
66 cm
88 cm
80 cm
72 cm
84 cm

9.Breadth of a rectangle is equal to the diagonal of the square whose side is 2.5√𝟐 cm. Ratio between length and breadth of rectangle is 3 : 1. Find the area of the rectangle (in cm2).
75
90
85
80
None of these

10.Equal distance is covered by a boat in upstream and in downstream in total 5 hours. Sum of speed of a boat in upstream and downstream is 40 km/hr. Speed of boat in still water is 600% more than the speed of stream. Find the approximate distance covered by boat in downstream (in km).
45
50
55
60
None of these

11.A and B entered into a partnership with Rs.800 and Rs.1600 respectively. From 9th months onward they each decided to invest Rs.100 more on starting of each month. If total annual profit is Rs.7700 then find the profit share of A.
Rs.2550
Rs.3200
Rs.2650
Rs.2450
Rs.2750

12.A starts a business, after 6 months B also join him with Rs.4500 and after 2 months of B’s joining C also join them with Rs.4500. If A gets approx. Rs 4900 out of total annual profit of Rs. 10,000 then find the approximate value of initial investment of A.
Rs.4800
Rs.4200
Rs.3600
Rs.4400
Rs.5200

Direction: The following questions are accompanied by three statements (I), (II), and (III). You have to determine which statement(s) is/are sufficient /necessary to answer the questions

13.What is distance between A and B ?

I. Two persons Amit and Abhi started simultaneously from A to B with their speed in ratio 4 : 5.

II. Abhi reached B one hour earlier than Amit.

III. Difference between speed of Amit and Abhi is 20 km/hr.

Only I and II
Only II and III
All I, II and III
Cannot be answered even including all three statement
None of these

14.What is the area of rectangle ?

I. If ratio of length and breadth of the rectangle is 3 : 2.

II. Circumference of a circle is 440 m and breadth of rectangle is 1/7 th of radius of the circle.

III. If length is 50% more than breadth.

Only III
Only II and either I or III.
Only II
All I, II and III
None of these

15.How many students failed in class 11th ?

I. 400 Students passed in class 11th.

II. No. of students failed in class 11th is 20% of those failed in class 12th.

III. Ratio of student appeared to that of failed in class 11th is 5 : 3.

Only I and III
Only II
Only I and II
All I, II and III
Cannot be answered even including all three statements.

16.What is the rate of interest?

I. S.I. accrued in two years on an amount at same rate of interest is Rs. 44,000.

II. The amount after some years on S.I. is Rs. 154000.

III. Difference between the C.I. and S.I. earned in two years on the same amount and at the same rate of interest is Rs. 120.

Only I and III
Only III
Only II and III
Cannot be answered even including all statement
None of these

17.What is the sum of two numbers?

I. The bigger no. is 6 more than the smaller no.

II. 40% of smaller no. is equal to 30% of bigger no.

III. The ratio b/w half of the bigger no. & one-third of smaller no. is 2 : 1.

Only II & III
Only I and II or I and III
Any two of the three statements
All statement is required
None of these

CASLET

Direction: Answer the questions based on the information given below:

Rahul goes to gym and runs 40 minutes on treadmill. For starting 15 minutes he runs at a uniform speed of 5 km/hr and after that he runs at a uniform speed of 9km/hr for remaining time. He runs total (A) km on treadmill. After that he comes to his house and get ready for office which is 45km away from his house. He reaches office in 1.5 hours at 9:30 a.m. In office he gives some work to his subordinates P1 and P2 at (B). P1 can complete that work in 6 hours while efficiency of P1 and P2 is in the ratio 5: 4. P1 and P2 together completes 75% of that work at 12:30 p.m. Rahul and P2 together can complete same work in 3 hours. Rahul is (C) % more efficient than P1. After that work he comes back to home in upstream (Speed of stream is 3km/hr and his speed in still water and distance between his house and office are same as earlier). He takes (D) hours to reach home. When he reaches home, two of his friends Aman and Raman come at his house, all three starts to play a game in which 2 dices are used by each person.  When only Rahul & Aman are playing, (E) was the number of outcomes in which first Rahul and then Aman throw their respective dices. In a game, all three throw their dices and each one of them get 8 as the sum of numbers in their dices and any one of two not get same outcomes. Winner is the one who gets highest number as the sum of the square of the number comes in dices. (F) Should be the outcomes of the dices of Raman if Raman is winner of the game.

18.What value will come at the place of ‘A’?

4.25 km
3.75 km
5 km
5.25 km
None of the given options

19.What value will come at the place of ‘B’?

10.45
None of the given options
11 am
10.30 am
10 am

20.What value will come at the place of ‘C’?

￼16 2/3%
20%
25%
￼33 1/3%
50%

21.What value will come at the place of ‘D’?

2 hours
1.5 hours
1 7/8 hours
1 2/3 hours
1 4/11 hours
￼
22.What value will come at the place of ‘E’?

72
42
36
108
54

SOLUTIONS:

ARITHMETIC SUM

1.Let amount of milk removed = 2x litre

So, amount of water added = x litre

Now → (165 − 2𝑥)/𝑥 = 5/3

x = 45 lit

2.At least one black can be chosen in two ways from each box:

Now, probability of choosing at least one black ball from first box = 1/2 × [ (2C1× 2C1)/4C2 + 2C2/4C2 ]= 5/12

Probability of choosing at least one black ball from 2nd box = 1/2 × [(4C1×12C1)/16C2 + 4C2/16C2] = 9/40

Final probability = 5/12 + 9/40 = (50 + 27)/120 = 77/120

3.Let speed of train B be 𝑥 m/s And length of train B be 𝑦 m

Then length of train A is 2𝑦 m

Speed of train A = 84 × 5/18 = 210/9 m/s = 70/3 m/s

A.T.Q, (2𝑦+𝑦)/10 = (70/3) − 𝑥 ………….(i)

and (2𝑦+𝑦)/ 22.5 = (70/3) − 2𝑥 …………….(ii)

solving (i) and (ii), 𝑦 = 50 m

4.Let, inner radius of cylinder be ‘𝑥’ cm.

4/3 𝜋(6)3 = 𝜋 × 32 (52 − 𝑥2 )

or, (4 × 6 × 6 × 6) / (3 × 32) = 25 − x2

or, 𝑥2 = 25 − 9

or, 𝑥 = 4 cm

Hence, thickness = 5 – 4 = 1 cm.

5.Profit ratio X & Y = (700 × 3) + (700 × 5/7 × 3) + (700× 5/7 + 200 × 3/5 )× 6 : 600 × 12

X:Y= 7320 : 7200= 183:180

∴ X’s share from profit = 183 × 726 /(183+180) = 𝑅𝑠. 366.

6.C.P. of 10 note books ⇒ 140 × 10 = 1400 Rs.

Profit on selling one pen ⇒ 50×200/100 = Rs 100

Number of pen required ⇒ 1400/100 = 14

7.Let speed of slower train = 2x

⇒ speed of faster train = 5x

ATQ, (150 + 200)/(2x + 5x) = 15

x = 10/3

Time required = 350 /[50/3 – 20/3] = 35 seconds

8.Let length and breadth of rectangle be L cm and B cm respectively So, ATQ

Area1= (L-6)×B

But this is square, so L-6=B

Area1= (L-6) × (L-6)

Case 2, Area2= L × (B+6),

L=B+6

So, Area2= L × L,

Given, Area2-Area1= 252

(L)2-(L-6)2=252

Solving this, L= 24

B= 18

Perimeter= 2(L+B)= 2(24+18)= 84 cm

9.Diagonal of Square = Side √2= 2.5√2 × √2 = 5 cm

Length of rectangle = 5 × 3 = 15 cm

Area of rectangle = 15 × 5 = 75 cm2

10.let speed of boat= X, speed of stream= Y

Upstream speed= X-Y

Downstream speed= X+Y

Sum of upstream & downstream= (X-Y) + (X+Y)= 2X

So, 2X= 40

X= 20 km/hr

Speed of boat : speed of stream= 600+100 : 100= 7:1

So speed of Stream= 20/7 km/hr

ATQ, D/( X-Y) + D/( X+Y) = 5

D/(120/7) + D/(160/7)= 5

D= 480×5/49= 48.97 km= 50 Km(approx)

11.Ratio of profit,

A : B = (800 × 8+ 900+ 1000+ 1100+ 1200) : (1600 × 8+ 1700+ 1800+ 1900+ 2000)

A : B = 53 : 101

Profit of A ⇒ 7700 ×53/154 = 2650 Rs.

12.Let initial investment of A = x

Ratio of profit A : B : C = 12 × x : 6×4500 : 4×4500

A :B:C = x : 2250: 1500

Now ATQ

x/(x+2250+1500) = 4900/10000

solving this we get,

x ≈ Rs 3600

DATA SUFFICIENCY:

13.From I, II & III

Let speed of Amit and Abhi be 4x and 5x km/hr respectively.

5x – 4x = 20

∴ x = 20 km/hr

So speed of Abhi= 20×5= 100 km/hr

Speed of Amit= 20×4= 80 km/hr

Let distance be D km

D/80 – D/100 = 1

∴ D = 80 × 100/20 = 400 km

All I, II and III required to answer.

14.From I and II, Let length and breadth be 3x m and 2x m respectively

2πr = 440 [r → radius of circle]

r = 70 m

∴ breadth = 70 ×1/7 =10 m

& length = 15 m

∴ Area = 10 × 15 = 150 m²

From statement III, length : breadth= 150 : 100= 3:2

So Statement I and III are same.

Only II and either I or III required to answer.

15.From statement I, Passed = 400

From statement III, Let number of appeared & Failed students be 5x and 3x respectively

2x = 400

⇒ x = 200

∴ failed = appeared – passed = 1000 – 400 = 600

So, Only I and III required to answer.

16.From statement I, PR × 2/100 = 44000

PR = 2200000…….(i)

From statement II, P + PRT/100 = 154000..................(ii)

From statement III, Difference = PR2/1002

PR2/1002 = 120………(iii)

by solving (i)&(iii) R can be found.

Only I and III required to answer

17.Let the smaller no. is x & bigger no. is y.

From statement I, y = x + 6

From statement II, (40/100) × 𝑥 = (30/100) × 𝑦

From statement III, 𝑦/2 : 𝑥 /3 = 2 : 1

⇒ 3y = 4x

statement II & From statement III give only ratio between the numbers, so we statement I also along one of II or III.

∴ from I and II or I and III we can find the Answer.

CASLET  EXPLANATION:

Rahul runs 40 minutes.
For starting 15 minutes
Speed = 5 km/hr
Distance = ￼ 15/60 × 5 = 5/4km
For next 25 minutes
Speed = 9 km/hr
Distance = 25/60 × 9= 15/4 ￼ km
Total distance = ￼ 5/4 +  15/4 = 5 km
So, he runs total 5 km on treadmill.
P1 can complete that work in 6 hours
Efficiency of P1 and P2 = 5: 4.
So, P2 can complete the work in ￼
6 * 5/4=7.5hours
So, the number of units of work done by them in one hours = ￼ 1/6 +1/7.5 = 3/10
So, they together can complete the work in
10/3 ￼hours
P1 and P2 together complete 75% of that work at 12:30 p.m.
100% of the work is completed in 10/3 ￼hours
So, 75% of the work will be completed in ￼10/300 * 75 = 2.5hours
So, in office Rahul gives some work to his subordinates P1 and P2 at 12.30 – 2.5 hours = 10 am.
Rahul and P2 together can complete same work in 3 hours.
￼ 1/Rahul + 1/7.5 = 1/3
Rahul = 5 hours
￼
So, Rahul can complete the whole work in 5 hours
Also, P1 can complete that work in 6 hours
So, ratio of the efficiency of P1 and Rahul = 6: 5
So, required percentage = ￼ (6-5)/5 * 100 = 20%
So, Rahul is 20 % more efficient than P1.
Distance between house and office = 45km.
Time taken to reach office = 1.5 hours at 9:30 a.m.
Speed = ￼ 44/1.5 = 30 km/hr
Speed of stream = 3km/hr
Therefore, required time = ￼ 45 /( 30 -3 ) = 45/27 = 5/3
So, he takes 1 2/3￼ hours to reach home.
Total outcomes in a single throw of 2 dice =
(1, 1) (1, 2) (1, 3) (1, 4) (1, 5) (1, 6)
(2, 1) (2, 2) (2, 3) (2, 4) (2, 5) (2, 6)
(3, 1) (3, 2) (3, 3) (3, 4) (3, 5) (3, 6)
(4, 1) (4, 2) (4, 3) (4, 4) (4, 5) (4, 6)
(5, 1) (5, 2) (5, 3) (5, 4) (5, 5) (5, 6)
(6, 1) (6, 2) (6, 3) (6, 4) (6, 5) (6, 6)
So, total number of outcomes in a single throw of two dice = 36
When first Rahul and then Aman throw their respective dices, total number of outcomes = 36 + 36 = 72
In a game, all three throw their dices and each one of them get 8 as the sum of numbers in their dices and any one of two not get same outcomes.
So, the required possibility = (2, 6) (3, 5) (4, 4) (5, 3) (6, 2)
Winner is the one who gets highest number as the sum of the square of the number comes in dices.
(2, 6) = ￼ 2² + 6² =40
(3, 5) = ￼ 3² + 5² = 34
(4, 4) = ￼ 4² + 5²= 32
(5, 3) = ￼ 5² + 3²=34
(6, 2) = ￼ 6² + 2²=40
So, Raman will get (2, 6) and the other two will get (3, 5) and (4, 4)
So, he runs total 5 km on treadmill.
So option (c) is the correct answer.