QUANT PRACTICE SET 37 FOR SBI PO PRELIM 2020 ( PIPE AND CISTERN)

QUANT PRACTICE SET 37 FOR SBI PO PRELIM 2020

SBI Clerk and SBI PO Prelims exam are going to be held in the upcoming months. We have already provided you with the PDFs of many topics of Quantitative Aptitude like Simplification/Approximation, Number Series,datainterpretation.important Arithmetic questions to prepare for SBI Clerk and PO Pre exam. Practicing these questions will help you to know about the level of the questions. To increase your speed and accuracy, enhance your calculations.

Follow us on TELEGRAM Web

START QUIZ

1.      Two pipes A and B can fill a tank in 20 hours and 25 hours respectively, while a third pipe C can empty 70% of the tank in 21 hours. All three pipes are opened in the beginning. After 12 hours C is closed. Find the time in which the tank will be full?

a.       13 2/3 hours

b.      11 7/8 hours

c.       16 ¾ hours

d.      15 5/9 hours

e.       None of these

2.      Two pipes A and B can fill a tank in 18 hours and 24 hours respectively, while a third pipe can empty 60% of the tank in 18 hours. All three pipes are opened in the beginning. After 12 hours c is closed. Find the time which the tank will be full?

a.       14 2/5 hours

b.      12 ¾ hours

c.       11 5/6 hours

d.      13 2/3 hours

e.       None of these

3.      Three pipes A, B and C can fill a tank in 10 hours. After working at it together for 3 hours, C is closed and A and B can fill the remaining part in 14 hours. How much time taken by C to fill the tank alone?

a.       18 hours

b.      20 hours

c.       24 hours

d.      22 hours

e.       None of these

4.      Three pipes A, B, C can fill a cistern in 10, 15, 18 hours respectively. If pipe A is kept open all the time and pipe B and C is opened alternatively for an hour then find in how many hours the tank will be filled?

a.       7 hours 25 mins

b.      5 hours 40 mins

c.       6 hours 12 mins

d.      7 hours 48 mins

e.       None of these

5.      Pipe A and Pipe B can fill a tank in 10 hours and 15 hours respectively while Pipe C can empty the full tank in 18 hours. If pipe A is opened at 7 am, Pipe B opened at 8:30 am and Pipe C at 10 am, then after 10 am, how much more time will be taken by all three pipes together to fill the tank?

a.       7 hour 18 min

b.      8 hour 36 min

c.       6 hour 42 min

d.      5 hour 24 min

e.       None of these

6.      P, Q and R can fill the tank in 12, 16 and 24 min respectively. All three began to fill the tank together but P and Q left 3 and 4 min respectively before filling the tank. Find the total time taken by all of them to fill the tank?

a.       12 min

b.      16 min

c.       8 min

d.      10 min

e.       None of these

7.      Two pipes A and B can fill a tank in 15 minutes and 25 minutes respectively. Both pipes are opened together andpipeBisclosed,5 minutes before the tank is filled completely. Calculate the total time required to fill the tank?

a.       11 ¼ min

b.      13 3/5 min

c.       12 7/8 min

d.      14 5/6 min

e.       None of these

8.      B is 5/4 times as efficient as A. If A can fill the 3/5 of the tank in 15 min, what fraction of the capacity of the tank would remain incomplete if B can fill the tank independently for 10 min only?

a.       2/3

b.      1/3

c.       ¼

d.      ½

e.       None of these

9.      P, Q and R can fill the tank in 15, 18 and 20 min respectively. All three began to fill the tank together but P and Q left 4 and 5 min respectively before filling the tank. In how much time will take to fill the tank?

a.       7 22/25 min

b.      8 30/31 min

c.       7 11/15 min

d.      8 4/7 min

e.       None of these

10.  Two inlet pipes can fill an empty tank in 15 and 18 hours and one outlet pipe can empty the tank in 20 hours. If all the pipes opened simultaneously, then how many hours required fill the full tank?

a.       11 8/11 hours

b.      12 5/7 hours

c.       13 11/13 hours

d.      9 5/9 hours

e.       None of these

11) Two pipes A and B alone can fill an empty tank in 20 min and 24 min respectively. Two pipes are opened simultaneously, after some time pipe B is closed. In how many minutes after pipe B is closed if the tank was filled in 15 minutes

a.       5 min

b.      6 min

c.       4 min

d.      4.5 min

e.       None of these

12) Two inlet pipes can fill an empty tank in 12 and 15 hours and one outlet pipe can empty the tank in 20 hours. In how many hours required filling the full tank if all the pipes opened simultaneously?

a.       6

b.      14

c.       10

d.      12

e.       8

13) Pipe P can fill an empty tank in 24 hours and pipe Q can fill the same tank in 16 hours. How many hours required to fill the whole tank, if P and Q fill alternatively doing the work, P begins on first hour?

a.       17 1/2

b.      19 1/3

c.       18 1/3

d.      18 3/5

e.       None of these

14) P alone can fill two-third of an empty tank in 28 hours and Q alone can fill three-fifth of the same tank in 21 hours. Pipe A can empty the full tank in 70 hours. Pipe P and Q opened simultaneously, after every 2 hours pipe A is opened for 1 hour then find the number of hours required to fill the whole tank

a.       33 1/11

b.      32 1/11

c.       33 1/3

d.      32 1/3

e.       11 1/11

15) Three pipes can fill an empty tank in 4 hours. If there is leakage in the tank it takes 1 hour more, then find the no of hours required to empty the full tank by leakage pipe alone

a.       12

b.      15

c.       24

d.      18

e.       20

SOLUTIONS:

1). Answer d

C can empty the tank in = (21/70)*100= 30 hours

Total units of work= 300

A’s one hour work = 300/20 = 15 units

B’s one hour work = 300/25 = 12 units

C’s capacity to empty in one hour = 300/30 = 10 units

When three pipes are opened simultaneously then in one hour they will fill,

(15+12-10) = 17 units

In 12 hours they will fill = 17*12= 204 units

After 12hrs, C will be closed

Time taken by A& B to fill the remaining tank = 96/27 = 3 15/27 = 3 5/9 hours

Total time will be = 12 + 3 5/9 = 15 5/9 hours

2). Answer a

C can empty the tank in =18/60*100= 30 hours

Total units of work= 360

A’s one hour work= 360/18= 20units

B’s one hour work = 360/24= 15 units

C’s capacity to empty in one hour= 360/30= 12 units

When three pipes are opened simultaneously then in one hour they will

(20+15-12)=23 units

In 12 hours they will fill= 23*12= 276 units

After 12 hr, C will be closed

Time taken by A & B to fill the remaining tank = 84/35= 2 2/5 hours

Total time = 12 + 2 2/5 = 14 2/5 hours

3). Answer b

Three pipes A, B and C can fill a tank in 8 hours.

A, B and C’s 1 hour work=1/10

A, B and C’s 3 hour work= 3/10

Remaining work= 1 – (3/10) = 7/10

The remaining part will be filled by A and B in 14 hours. Then,

= > (7/10) *(A+B) = 14

= > (A+B)’s whole work= 14*(10/7) = 20 hr

(A+B)’s 1 hour work= 1/20

A, B and C’s 1 hour work = 1/10

C’s 1 hour work= (A+B+C) – (A+B)

= > (1/10) – (1/20)

= > 1/20

C can fill the tank in 20 hours.

4). Answer c

Total units of work= 90

A’s one hour work = 9

B’s one hour work = 6

C’s one hour work = 5

Work done by three pipes in 2 hours = 15 + 14 = 29 units

Work done in 6 hours= 29*3 = 87 units

Remaining will be done by pipe A and B = 3/15 = 1/5 hours

Total time required= 6 1/5 hours = 6 hours 12 mins

5). Answer d

Let capacity of tank = 90 lit (LCM of 10, 15, 18)

A fills 90/10 = 9 liter/hour

B fills 90/15 = 6 liter/hour

C empties 90/18 = 5 liter/hour

Till 10 am 9*3 + 6*1.5 = 27 + 9 = 36 liters

Remaining volume to be filled =90 – 36 = 54 liters

After 10 am, when all pipes are opened. 9 + 6 – 5= 10 liters/hr is filled.

Required time = 54/10 = 5 4/10 = 5 2/5 hour = 5 hour 24 min

6). Answer c

(x-3)/12 + (x-4)/16 + x/24 =1

(4x – 12 + 3x – 12 + 2x)/48 = 1

9x – 24 = 48

9x = 72

X = 8 min

7). Answer a

Let total capacity = 75 litres (LCM of 15 and 25)

A = 5 litres/min

B = 3 litres/min

A+B fill 75 litres

A can fill 5*5 = 25 litres in 5 min

But B was closed 5 min before the tank is filled. So A+B together filled (75-25) = 50 litres

50 litres can be filled by A + B in,

= > (50/8) = 6 1/4

Total time = 6 1/4 + 5 = 11 ¼ min

8). Answer d

B is 5/4 times as efficient as A. So,

A and B’s time =>5 : 4

A can fill the 3/5 of the tank in 15 min

=> (3/5) * work = 15 min

=> Whole work = 25 min

A takes 25 min to fill the tank, So, B takes,

=> 5’s =25

=>1’s = 5

B can fill the tank in, 20 min

B can fill the tank independently for 10 min only.

B’s 10 min work = 10/20 = 1/2

Remaining = 1- 1/2 = ½

Half of the tank will remain incomplete.

9). Answer b

(x – 4)/15 + (x – 5)/18 + x/20 =1

(12x – 48 +10x – 50 + 9x)/180 =1

31x – 98 = 180

31x = 278

X = 278/31 = 8 30/31 min

10). Answer c

If all the pipes are opened simultaneously, then in,

= > (1/15) + (1/18) – (1/20)

= > (12 + 10 – 9)/180

= > 13/180

Required hours = 180/13 = 13 11/13 hours

11) Answer b

15/20+x/24=1

18+x=24=>x=6 minutes

12) Answer c

LCM of 12, 15 and 20 =60 units

Required no of hours = 60/(5+4-3)=60/6=10 hours

13) Answer b

LCM of 24 and 16 =48 units

1 cycle (2 hours) = 5 units

9^th cycle (18 hours) = 45 units

19^th hour =2 units

Required no of hours = 18+1+1/3=19  1/3 hours

14) Answer a

LCM of 42, 35 and 70 = 210

1 cycle (3 hours) = 2*(5+6) + 3=22-3=19

11^th cycle = 209 units completed

Remaining = 210-209=1 units

Required no of hours = 33+1/11=33  1/11

15) Answer e

Required no of hours = ¼ -1/5 =(5-4)/20=1/20