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QUANT PRACTICE SET 32 FOR SBI PO PRELIM 2020

QUANT PRACTICE SET 32 FOR SBI PO PRELIM 2020


SBI Clerk and SBI PO Prelims exam are going to be held in the upcoming months. We have already provided you with the PDFs of many topics of Quantitative Aptitude like Simplification/Approximation, Number Series,datainterpretation.important Arithmetic questions to prepare for SBI Clerk and PO Pre exam. Practicing these questions will help you to know about the level of the questions. To increase your speed and accuracy, enhance your calculations.

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                           START TEST


1.Ten years ago, A’s age was half that of B. If the ratio of the present ages of A and B is 3 : 5, find the total of their present ages.
A) 50
B) 60
C) 65
D) 80
E) None of these

2.3 children A, B and C play a game. A puts Rs 50 and B puts Rs 45. At the end of 4 months, A withdraw half his capital and at the end of 6 months B also withdraws half of his capital. C then enters with a capital of Rs 70. At the end of a year, in what ratio the pofit will be divided?
A) 81 : 80 : 67
B) 60 : 81 : 84
C) 70 : 81 : 84
D) 84 : 80 : 81
E) None of these

3.13 shirts costs Rs 50 each, 15 pants Rs 60 each, and 12 ties costs Rs 65 each. What is the average value of each article?
A) Rs 58
B) Rs 58.25
C) Rs 58.50
D) Rs 58.75
E) Rs 59


4.A sum of Rs 2600 is lent in two parts such that the interest on one part at 10% for 5 years is equal to that on another part at 9% for 6 years. Find the difference in two sums.
A) Rs 100
B) Rs 150
C) Rs 200
D) Rs 300
E) Rs 400



5.A vessel contains milk and water with a total quantity of 80 litres. 70% of milk and 30% of water is taken out of the vessel. It is found that the vessel is vacated by 55%. What is the initial quantity of milk and water respectively (in litres)?
A) 60, 20
B) 50, 30
C) 55, 25
D) 45, 35
E) 40, 40

Directions (6-10):Following question contains two equations as I and II. You have to solve both equations and determine the relationship between them and give answer as,

6)
I) x + 9x + 20 = 0
II) y + 13y + 42 = 0

A. x > y
B. x ≥ y
C. x = y or relationship can’t be determined.
D. x < y
E. x ≤ y

7)
I) x – 18x + 72 = 0
II) y – 21y + 108 = 0

A. x > y
B. x ≥ y
C. x = y or relationship can’t be determined.
D. x < y
E. x ≤ y

8)
I) 2x – 2x – 84 = 0
II) y – 2y – 48 = 0

A. x > y
B. x ≥ y
C. x = y or relationship can’t be determined.
D. x < y
E. x ≤ y

9)
I) 2x + y = 34
II) x + 3y = 47

A. x > y
B. x ≥ y
C. x = y or relationship can’t be determined.
D. x < y
E. x ≤ y

10)
I) x + 32x – 144 = 0
II) y – 31y + 108 = 0

A. x > y
B. x ≥ y 
C. x = y or relationship can’t be determined.
D. x < y
E. x ≤ y





SOLUTIONS:

1.Answer & Solution
D) 80
Explanation:
Let the present ages of A and B are 3x and 5x.
Then, 10 yrs ago, (3x-10) = ½ * (5x-10)
Solve, x = 10
So present ages of A and B are 30 and 50 resp, their sum = 80

2.Answer & Solution
E) None of these
Explanation:
A’s share : B’s share : C’s share
50*4 + 50/2 * 8 : 45*6 + 45/2 * 6 : 70*6
80 : 81 : 84

3.Answer & Solution
B) Rs 58.25
Explanation:
Average = 13*50 + 15*60 + 12*65 / 13+15+12

4.Answer & Solution
A) Rs 100
Explanation:
Interests are equal. So,
1st part *5*10/100 = 2nd part * 6*9/100
This gives, 1st part : 2nd part = 27 : 25
So 1st part = 27(27+25) * 2600 = 1350
2nd part = 2600 – 1350 = 1250
So diff = Rs 100

5.Answer & Solution
B) 50, 30
Explanation:
By method of allegation:
Milk                    water
70%                   30%
.           55%
25%                   15%
25 : 15 = 5 : 3
Milk = 5/(5+3) * 80 = 50 l
Water = 80 – 50 = 30 l

6) Answer: A
 x + 9x + 20 = 0
 x + 4x + 5x + 20 = 0
x(x + 4) + 5(x + 4) = 0
 (x + 5)(x + 4) = 0 x = -5,
-4 y + 13y + 42 = 0
y + 6y + 7y + 42 = 0
y(y + 6) + 7(y + 6) = 0
(y + 7)(y + 6) = 0 y = -7, -6
x > y

7) Answer: C
 x – 18x + 72 = 0
x – 12x – 6x + 72 = 0
x(x – 12) – 6(x – 12) = 0
 x = 6, 12
7/9 y – 21y + 108 = 0
y – 12y – 9y + 108 = 0
y(y – 12) – 9(y – 12) = 0
(y – 9)(y – 12) = 0
y = 9, 12
Relationship between x and y cannot be established.

8) Answer: C
2x – 2x – 84 = 0
2x – 14x + 12x – 84 = 0
2x(x – 7) + 12(x – 7) = 0
(2x + 12)(x – 7) = 0
x = -6, 7
y – 2y – 48 = 0
y – 8y + 6y – 48 = 0
y(y – 8) + 6(y – 8) = 0
(y + 6)(y – 8) = 0
y = -6, 8
Relationship between x and y cannot be established

9) Answer:
D 2x + y = 34 ——–(1)
x + 3y = 47 —–(2)
(1) – (2) * 2 -5y = -60
8/9 y = 12 x = 47 – 36 = 11
x < y

10.Answer: E
x + 32x – 144 = 0
x + 36x – 4x – 144 = 0
x(x + 36) – 4(x + 36) = 0
(x – 4)(x + 36) = 0
x = 4, -36
y – 31y + 108 = 0
y – 27y – 4y + 108 = 0
y(y – 27) – 4(y – 27) = 0
(y – 4)(y – 27) = 0
y = 4, 27 x ≤ y