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REASONING FOR SBI CLERK AND RBI ASSISTANT MAINS


We bring you the complete and important daily Reasoning  to achieve more marks in Banking, Insurance, UPSC, SSC, CLAT, Railways and all other competitive Exams. We prepare it based on our daily current affairs.Hope you like it.

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START QUIZ
Directions (1 – 5): Study the following information carefully to answer the given questions
A number arrangement machine when given an input of words/numbers, rearranges them following a particular rule in each step. The following is an illustration of input and steps of rearrangement.
Input: 33 data 26 45 memo sweet 64 angle 14 utter 21 play
Step 1: angle 33 data 26 45 memo sweet 64 utter 21 play 16
Step 2: 19 angle 33 data 26 45 memo sweet 64 play 16 utter
Step 3: data 19 angle 33 45 memo sweet 64 play 16 utter 28
Step 4: 31 data 19 angle 45 memo 64 play 16 utter 28 sweet
Step 5: memo 31 data 19 angle 64 play 16 utter 28 sweet 47

Step 6: 62 memo 31 data 19 angle 16 utter 28 sweet 47 play
This is the final arrangement and step 6 is the last step for this input.
Input: caller 25 key 22 live 12 63 theme 33 money 58 book
  1. What is the position of ‘14’ in step 4 from right end?
    A. 7th
    B. 9th
    C. 5th
    D. 4th
    E. 8th
  2. In step 5, if ‘31’ is related to ‘book’ in the same way as in step 3, ‘key’ is related to ‘33’ in a certain way, then in step 4, ‘58’ is related to which of the following in the same way?
    A. theme
    B. money
    C. 27
    D. live
    E. 63
  3. What is the sum of numbers – 4th from the left end in step 2 and 4th from the right end in step 4?
    A. 58
    B. 43
    C. 32
    D. 65
    E. 39
  4. In which of the following step number do the words/numbers ‘63 33 money 58’ occur together?
    A. 2
    B. 4
    C. 3
    D. 5
    E. In more than 1 steps
  5. Which of the following is the last but one step of given input?
    A. 31 caller 20 book key live 63 58 14  theme 27 money
    B. key 31 caller 20 book live 63 14  theme 28 money 60
    C. 31 caller 20 book key live 63 59 14  theme 27 money
    D. key 31 caller 20 book live 63 14  theme 27 money 60
    E. None of these
Solution-
In the given example words start with – a, d, m, p, s, u (in alphabetical order)They are taken as —   a…u…d…s…m…p
Numbers in ascending order – 14, 21, 26, 33, 45, 64 (+2, -2, +2, -2, +2, -2)
Now::
Input: caller 25 key 22 live 12 63 theme 33 money 58 book
Step 1: book caller 25 key 22 live 63 theme 33 money 58 14
Step 2: 20 book caller 25 key live 63 33 money 58 14  theme
Step 3: caller 20 book key live 63 33 money 58 14  theme 27
Step 4: 31 caller 20 book key live 63 58 14  theme 27 money
Step 5: key 31 caller 20 book live 63 14  theme 27 money 60
Step 6: 61 key 31 caller 20 book 14  theme 27 money 60 live
Directions (6-10) : Study the information and answer the questions :
The questions are based on following coding formats:
$ – North
@ – South
# – East
% – West
! – Either 3 or 8 m
& – Either 4 or 9 m
© – Either 1 or 6 m
Examples: P@Q means P is South of Q, P$%Q means P is North-West of Q, P#!Q means P is East of Q at a distance of either 3 or 8 m.
Conditions given are as:
I. A%!B
II. A$!C
III. C%&D
IV. E@&B
V. D$©F
VI. E#F
6. If distance between points P and D is 8 m, P$D, P%B, find the distance between points P and B.
A. 4 m
B. 5 m
C. 3 m
D. 8 m
E. None of these
7. Given that L@!A, and L$C, find the distance between points L and C.
A. 2 m
B. 7 m
C. 8 m
D. 3 m
E. 5 m
8. If K@C, then which of the following is definitely false?
A. F#K
B. E$#K
C. A$K
D. B$%K
E. K@%D
9. If distance between points D and F is greater than distance between points B and E, then which of the given conditions above will contradict given that E#F is definitely true?
A. A%!B
B. A$!C
C. C%&D
D. E@&B
E. D$©F
10. If distance between points B and E is 4 m, find the distance and direction of point A with respect to point D?
A. 8 m
B. 10 m
C. 11 m
D. 5 m
E. 4 m
Solution-
 6. Since E is east of F, so AB should be greater than CD, which is possible with CD = 4, AB = 8

Point P is 8 m north of point D, point P is west of point BSo PB = AB-CD = 8-4 = 4 m 

7. For L to be north of C and A to be north of L, length AL should be 3, and AC be 
8. so LC = AC-AL = 8-3 = 5 m  8. We have to find the one which is definitely false, for 1st and 2nd options, there is a possibility. In D, B is north-west of K, but B will be definitely north-east of K. 
9. For Q, conditions will be DF = 6, and BE = 4. Now keeping F west of E as same, we get
So in this, A is south of C.

10. If BE = 4, then DF = 1 and AC = 3, soAD = √(AC2+CD2) = √(9+16) = 5 m