We brings you daily Current affairs, daily Current Affairs Quiz, weekly Current Affairs, weekly Current Affairs Quiz to enhance your preparation for upcoming exams. We also provide articles related to quant, reasoning, English, ssc etc .

Search here

Breaking

QUANT PRACTICE SET 6 FOR SBI PO PRELIMS



SBI Clerk and SBI PO Prelims exam are going to be held in the upcoming months. We have already provided you with the PDFs of many topics of Quantitative Aptitude like Simplification/Approximation, Number Series,datainterpretation.important Arithmetic questions to prepare for SBI Clerk and PO Pre exam. Practicing these questions will help you to know about the level of the questions. To increase your speed and accuracy, enhance your calculations.

Follow us on TELEGRAM








START TEST



Study the following table carefully and answer the questions that follow: The table shows the discount % given by stores on different items. The Market Price of any article on all stores is same. Some values are missing. Answer the questions on the basis of given table and information in question.







Q1) If the average SP of article II by in all the stores is Rs 2568, Find the MP of article II.
A) Rs 3200
B) Rs 4500
C) Rs 3600
 D) Rs 4300
E) Rs 4000

Q2) Difference between SP of article I by stores A and B is Rs 486, Find the SP of same article by store C.
 A) Rs 3506
B) Rs 4005
C) Rs 4808
D) Rs 4104
E) Rs 3205

Q3) Average SP of article III by stores A and B is Rs 3608, by stores B and C is Rs 3300. Find the SP of article III by store C.
A) Rs 2984
B) Rs 3122
C) Rs 3080
D) Rs 2764
E) Rs 3452

Q4) Store A earned 10% profit by selling product V. If CP of articles at all articles is same, find the ratio of profits by B and C in selling V.
A) 6 : 15
B) 9 : 16
C) 8 : 15
D) 6 : 13
E) 9 : 14

Q5) Ratio of discounts on article IV by stores A and B is 2/3. Difference in SP of article IV by stores A and C is Rs 432. If SP of article IV by store A is Rs 216 more than that by store B, find the SP of article IV by store C?
A) Rs 2138
B) Rs 2687
C) Rs 2736
D) Rs 2522
E) Rs 2544


6.A and B started a business with Rs 10,000 and Rs 15,000 respectively. After 6 months C joined them with Rs 20,000.
Quantity I: B′s share in total profit of Rs 4,00,000 at the end of 2 years.
Quantity II: Annual Salary of Rohit after tax deduction if he earns Rs 20,000 per month and pays a tax of 20% each month.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≤ Quantity I
E) Quantity I = Quantity II or Relation cannot be established

7.A can do a work in 16 days. B is 60% more efficient than A.
Quantity I: Time taken by A and B together to do the work.
Quantity II: Time taken by A and B to do the work together when A works at double his original efficiency and B works at half his original efficiency.
 A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established

8.The value of a machine depreciates at 10% per annum
Quantity I: Value of machine after 2 years, if the present value of machine is Rs 96000
Quantity II: Distance travelled by a taxi in 1 year, if it travels at a constant speed of 40kmph and covers 213 kilometers everyday.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation

9.A rectangular plot measuring 80 meters by 40 meters is to be enclosed by wire fencing along the boundary of the plot. The fence will be tied on poles that will be placed along the boundary.
Quantity I: Number of poles required for fencing if each pole is at a distance of 24 meters.
Quantity II: Radius of a circle whose area is 10% of the area of the rectangular plot.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I
E) Quantity I = Quantity II or Relation cannot be established

10.A bag contains 3 red, 4 green and 2 blue balls. Two balls are drawn at random.
Quantity I: Probability that None of the ball drawn is blue.
Quantity II: Fraction of work completed by A in 7 days if he is 20% more efficient than B who can complete the work in 12 days.
A) Quantity I > Quantity II
B) Quantity I ≥ Quantity II
C) Quantity II > Quantity I
D) Quantity II ≥ Quantity I

SOLUTIONS

1.View Answer
 Option C
Solution: SP by store A = (100-28)/100 * MP = 72% of MP, by B = 82% of MP, by C = 60% of MP So (72+82+60)/3 * MP/100 = 2568 Solve, MP = Rs 3600

2.View Answer
Option D
 Solution: Difference in SP = 93% of MP – 84% of MP So 9% of MP = 486 Solve, MP = 5400 So SP by store C = 76% of 5400 = Rs 4104

3.View Answer
Option C
Solution: Let x% discount by store B So [84 + (100-x)]/2*100 * MP = 3608 And [70 + (100-x)]/2*100 * MP = 3300 Put value of (100-x) from 1 equation to another and solve for MP MP = Rs 4400 So SP by store C = 70/100 * 4400 = Rs 3080

4.View Answer
Option E
Solution: MP = x SP by A = 88% of x So CP by A = 100/110 * 88/100 *x = 4x/5 Now CP is same SP by B = 89x/100, so profit of B = 89x/100 – 4x/5 = 9x/100 SP by C = 94x/100, so profit of B = 94x/100 – 4x/5 = 14x/100 So required ratio = 9 : 14


5.Option C
Solution: x/18 = 2/3 So discount by A = 12% Now 88% of MP = 82% of MP + 216 Solve, MP = Rs 3600 Now: let y% discount by store C [88 – (100-y)]/100 * MP = 432 MP = Rs 3600 Solve, y = 24% So SP by C = 76% of 3600 = Rs 2736

6.View Answer
Option C
Explanation: I: A:B:C = 10000*24 : 15000*24 : 20000*18=2:3:3 B=3/8 *4,00,000= Rs 1,50,000 II: Salary after deducation = 20,000*12*80/100 = Rs 1,92,000 Hence I < II

7.Option A
Explanation: I: A=16 days ; B = 16 * 100/160=10 days A+B together = 16*10/(26)=80/13 days II: A = 16 days ; B = 10 days A(double efficiency) = 8 days ; B(half efficiency) = 20 days A+B together = 80/14 hence I > II

8.
View Answer
Option E
Explanation: Value of machine after 2 years = 96000*90/100*90/100= Rs 77,760 II: Here we do not need speed, as we can find the total distance travelled by the everyday distance. If the year is leap year then total distance travelled = 213*366= 77,958 km if non leap year then =213*365 = 77,745 km hence relation cannot be established.

9.View Answer
 Option C
 Explanation: I: Perimeter= 2(80+40)=240 No. of poles = 240/24=10 II: Area of circle = 320 =>22/7*r*r=320 r=101.81 => r >10 Hence II > I

10.View Answer
Option C
Explanation: I: 7C2/9C2=7/12 II: A-> 10 days => fraction of work in 7 days = 7/10 Hence II > I