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Solutions
S1. Ans. (b)
S2. Ans. (d)
S3. Ans. (b)
S4. Ans. (e)
S5. Ans. (d)
S6. Ans. (d)
Sol.
Let total work be 144 units.
(LCM)
So, efficiency of Shivam and
Maanik are 3 units/day and 2 units/day respectively.
Time taken when both working
together =144/5 𝑑𝑎𝑦𝑠
Time taken by Amit to finish
work alone =144/5 × 5/6=24 𝑑𝑎𝑦𝑠
So, efficiency of Amit =144/24=6 𝑢𝑛𝑖𝑡𝑠/𝑑𝑎𝑦
Let Maanik worked for T days.
ATQ
5×𝑇+9×6=144𝑇=90/5=18 𝑑𝑎𝑦𝑠
Total work done by Maanik =18×2=36 𝑢𝑛𝑖𝑡𝑠
So, required part of work =36/144=1/4
S7. Ans. (b)
Sol.
Let the labourer present for x days.
ATQ
170×𝑥−40×(35−𝑥)=3640
170𝑥−1400+40𝑥=3640
210𝑥=5040
𝑥=24
So, required no. of days =35−24=11 𝑑𝑎𝑦𝑠
S8. Ans. (e)
S9. Ans.(e)
S10. Ans.(d)
