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__START QUIZ__**Directions (1-5): The following questions are accompanied by two statements A and B. You have to determine which statements(s) is/are sufficient/necessary to answer the questions.**

(a) Statement

**A**alone is sufficient to answer the question but statement**B**alone is not sufficient to answer the questions.
(b) Statement

**B**alone is sufficient to answer the question but statement**A**alone is not sufficient to answer the question.
(c) Both the statements taken
together are necessary to answer the questions, but neither of the statements
alone is sufficient to answer the question.

(d) Either statement

**A**or statement**B**by itself is sufficient to answer the question.
(e) Statements

**A**and**B**taken together are not sufficient to answer the question.**Q1. An equilateral triangle is inscribed in a circle. What will be the difference between the area of circle and area of triangle?**

(A) Radius of circle is given

(B) Sum of the perimeter of
triangle and circle is given.

**Q2. Is ‘n’ even or odd, if n is a natural number.**

(A) 2

^{n}+ 1 is divisible by 3
(B) 4

^{n}− 1 is divisible by 3**Q3. A shopkeeper gets a loss of 70 Rs. when he sold an article at 20% discount on M.P. Find cost price of Article.**

(A) % of mark up above cost
price is equal to % discount given on M.P.

(B) when no discount is given,
article sold at profit of 350 Rs.

**Q4. ‘X’ mark up an article 50% above its cost price. Find the cost price of article.**

(A) ‘X’ gave Rs 60 discount on
mark price and earn 20% profit.

(B) If ‘X’ gave two successive
discounts of 10% each then he will earn Rs 43 as profit.

**Q5. Amit tells truth 2 times out of x times while Ankush tells truth 5 times out of ‘y’ times. Find the product of ‘x’ and ‘y’**

(A) Probability that Amit and
Ankush contradict with each other on facts is 50%

(B) Probability that both
tells truth is 20%

**Direction (6-10): Read the data carefully and answer the following questions.**

There are four multiplexes in Gurgaon sector 29 i.e. (A, B, C & D) and each multiplex plays movie at two time slots i.e. 3 pm and 5 pm. Total people watching movie at 3 pm in B is50/3% more than total number of people watching movie in A at the same time, while total number of people watching movie at 5 pm in A is 132 more than that of total number of people watching movie in B at 3 pm. Total number of people watching movie in C at 3 pm is 300 more than the average number of people watching movie in A & B at 3 pm, while total number of people watching movie in B at 5 pm is 68 more than the total number of people watching movie in A at 5 pm & total number of people watching movie in C at 5 pm is 25% more than total number of people watching movie in B at 5 pm. Average number of people watching movie (in all four multiplexes) at 3 pm and at 5 pm is 4200 and ratio of total number of people at 3 pm in all four multiplex to total number of people at 5 pm in all four multiplex is 3 : 4. Total number of people watching movie in D at both time slots is 2448 and total number of people watching movie in D at 5 pm is 188 more than total number of people watching movie at same time in C.

**Q6. Lf ratio of number of male to number of female watching movie at 3 pm in A is Q“;**

**3, then ﬁnd the total number of male watching movie at 3 pm in A is what percent of total**

**Q7. Find the ratio of total number of people watching movie at 5 pm in B to total number of people watching movie at 3 pm in C?**

(a) 26 : 29

(b) 25 : 27

(c) 26 : 27

(d) 26 : 31

(e) None of these

**Q8. Total number of people watching movie at 5 pm in D is what percent more than**

**Q9. Find the average number of people watching movie at 3 pm in B, C & D?**

(a) 960

(b) 840

(c) 640

(d) 720

(e) 1080

**Q10. Total number of people watching movie at 5 pm in A is what percent of total**

**Solutions**

S1. Ans.(d)

Sol.

Form A → Let radius of circle =
r

Then side of equilateral Δ =√3𝑟

Area of equilateral triangle
and circle can be find out and required difference can also be find out easily.

From B → Let radius of circle
=r

⇒ side
of equilateral triangle =√3 r

Sum of peremeter of triangle
and circle is given. By this value of ‘r’ can be find out and after this
required difference can be find out easily. Hence, either only A or only B is sufficient
to answer the question

S2. Ans.(a)

Sol.

From A → 2

^{𝑛}+1 is divisible by 3
⇒ n
=1, 3, 5, 7….

⇒ n = odd

From B) → 4

^{𝑛}−1 is divisible by 3
⇒ n =1, 2, 3…….

⇒ ‘n’ can be even as well as odd

Hence, Only A is sufficient to
answer the question

S3. Ans.(d)

Sol.

From A→

Discount % = 20% = Mark up%

If cost price is 100x then
Markup price 120x and selling price is → 96x

So ATQ,

100x – 96x = 70

C.P=100x=70/4x ×100x=1750

From B→

Let mark up price is → 100x

Then selling price is → 80x

ATQ,

100x – 80x = 350 + 70

20x = 420

100x = 2100

80x = 1680

C.P. → 1680 + 70 = 1750

So Either A or B alone
required.

S4. Ans.(d)

Sol.

Let CP = 200x

⇒ MP = 300x

From A → SP = 300x – 60

200𝑥× 120/100=300𝑥−60 ⇒60𝑥=60

⇒ CP = 200x = 200

From B → Two successive
discount =10+10−(10×10)/100=19%

S.P =200x + 43 =300𝑥 × 81/100

200x + 43 = 243x

x = 1

CP = 200x = 200

Hence, either alone A or alone
B is sufficient to answer the question.

S5. Ans.(b)

Sol.

Probability that Amit tells
truth =2/𝑥

Probability that Amit tells lie
=𝑥−2/𝑥

Probability that Ankush tells
truth=5/𝑦

Probability that Ankush tells
lie =(𝑦−5)/𝑦

From A→ 2/𝑥 × (𝑦−5)/𝑦+(𝑥−2)/𝑥 × 5/𝑦=12

From B → 2/𝑥 × 5/𝑦=15 ⇒𝑥𝑦=50

Hence only B is sufficient to
answer the question.

**Solution (6-10))**

S6. Ans.(e)

S7. Ans.(c)

S8. Ans.(d)

S9. Ans.(a)

S10. Ans.(e)