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In a state competition, eight students, viz A, B, C, G, T, V, W and X are representing different Schools, viz SVM, DAV, DPS, PPT, BVM, MVN, KCM and JPS, but not necessarily in the same order. All of them are sitting around a circular table facing the centre.C and X and also their immediate neighbours do not represent DPS. Only one person sits between W and the student who represents DPS. Students of PPT and SVM are immediate neighbours of each other. C represents neither BVM nor PPT. Only one person sits between A and the one who represents MVN. A does not represent either DPS or SVM. C sits third to the right of X. X represents JPS. T is not an immediate neighbour of either C or X. The one who represents DAV is an immediate neighbour of T. Three people sit between X and the student of KCM. B is not representing either DPS or DAV. V sits third to the left of T.

1. Who among the following represents SVM?
1) B
2) C
3) T
4) V
5) Cannot be determined

2. Who among the following represent immediate neighbours of
V?
1) A, B
2) A, G
3) T, W
4) A, C
5) A and the student of BVM

3. Which of the following is true regarding W?
1) W sits second to the right of A.
2) W represents PPT.
3) W sits between B and the student of JPS.
4) Only one person sits between W and the student of SVM.
5) None is true

4. How many persons sit between G and the student of PPT, when
counted anticlockwise from G?
1) None
2) One
3) Two
4) Three
5) Four

5. Which of the following is true?
1) G represents DPS.
2) Only one person is sitting between the students of PPT and BVM.
3) The student of SVM is an immediate neighbour of W.
4) One person sits between X and the student of DPS.

5) None of these

Directions (6-10): Study the following information carefully and answer the given questions. A word and number arrangement machine when given an input of words and numbers rearranges them following a particular rule. The following is an illustration of input and rearrangement.
Input: 42 74 TBEF WRAK 95 NLDG 31 65 KEOR QCOF
Step I: 90 42 74 TBEF NLDG 31 65 KEOR QCOF AKRW
Step II: 79 90 42 NLDG 31 65 KEOR QCOF AKRW BEFT
Step III: 60 79 90 42 NLDG 31 KEOR AKRW BEFT CFOQ
Step IV: 47 60 79 90 31 KEOR AKRW BEFT CFOQ DGLN
Step V: 26 47 60 79 90 AKRW BEFT CFOQ DGLN EKOR
Step V is the last step of the rearrangement.
As per the rules followed in the above steps, find out in each of the following questions the appropriate steps for the given input
. Input: IMRE 40 69 RBHI 86 PMCN 25 KDSM 57 VATW
Q6. How many steps would be needed to complete the arrangement?
(a) V
(b) VII
(c) VI
(d) IV
(e) None of these

Q7. Which step number would be the following output?
45 52 64 91 IMRE 25 ATVW BHIR CMNP DKMS
(a) II
(b) III
(c) V
(d) IV
(e) None of these

Q8. Which of the following would be Step III?
(a) 52 64 91 IMRE 40 25 KDSM ATVW CMNP BHIR
(b) 52 64 91 IMRE 40 25 KDSM ATVW BHIR CMNP
(c) 64 52 91 IMRE 40 25 KDSM ATVW BHIR CMNP
(d) 52 91 64 IMRE 40 25 KDSM ATVW BHIR CMNP
(e) None of these

Q9. Which of the following element would be the 4th to the left of the one which is 8th from the left in the step IV?
(a) 91
(b) IMRE
(c) 64
(d) CMNP
(e) None of these

Q10. In Step V, which of the following element would be on eighth position from the right end?
(a) ATVW
(b) BHIR
(c) 64
(d) 52
(e) None of these

SOLUTION:

S1. Ans.(d)
S2. Ans.(d)
S3. Ans.(e)
S4. Ans.(c)
S5. Ans.(b)

6 -10.
Solutions (6-10): Logic: As a first step let’s first understand the logic behind the Output. Words are arranged from right end and numbers are arranged from left end. In each step one word and one number are arranged. Word – Words are arranged in ascending order from left to right according to the English alphabetical order. In the first step the word starting with the letter having higher place value in the English alphabet is arranged first on the right end and also the letters of the word are arranged in increasing alphabetical order within the word. Number- Numbers are arranged in ascending order from left to right. In the firs step the highest number is arranged first and then in the second step 2nd highest numbered gets arranged and so on till the last step and also after rearranging the numbers add 5 in the even number and subtract 5 in the odd numbers.

Input: IMRE 40 69 RBHI 86 PMCN 25 KDSM 57 VATW
Step I: 91 IMRE 40 69 RBHI PMCN 25 KDSM 57 ATVW
Step II: 64 91 IMRE 40 PMCN 25 KDSM 57 ATVW BHIR
Step III: 52 64 91 IMRE 40 25 KDSM ATVW BHIR CMNP
Step IV: 45 52 64 91 IMRE 25 ATVW BHIR CMNP DKMS
Step V: 20 45 52 64 91 ATVW BHIR CMNP DKMS EIMR
Step V is the last step of the rearrangement.

S6. Ans.(a)
S7. Ans.(d)
S8. Ans.(b)
S9. Ans.(a)
S10. Ans.(d)