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QUANT FOR SBI PO PRELIMS 3


We bring you the complete and important daily QUANT  to achieve more marks in Banking, Insurance, UPSC, SSC, CLAT, Railways and all other competitive Exams. We prepare it based on our daily current affairs.Hope you like it.

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Direction (1 - 5): Study the following information
carefully and answer the questions given below.
Three vendors A,B & C sell pizzas (veg + non-veg) in
Week I. Veg & Non-veg pizzas sold by A are in the
ratio 9:7, & those sold by B are in the ratio 3:4. Total
pizzas sold by C are 108, out of which veg & non-veg
pizzas of C are in the ratio 7:5. Total pizzas sold by A,
B & C together are 376. Veg pizzas sold by A is 20%
more than the veg pizzas sold by B

11) Find the ratio between the veg pizzas sold by A and C.

a) 8: 7
b) 1: 2
c) 3: 2
d) 7: 8
e) 5: 6


12) Find the sum of non – veg pizzas sold by all the vendors.

a) 178
b) 145
c) 156
d) 175
e) 181
13) The veg pizzas sold in B is what percentage of
non – veg pizzas sold in B?

a) 80%
b) 85%
c) 75%
d) 70%
e) 60%
14) Find the average veg pizzas sold in A and B.

a) 44
b) 60
c) 72
d) 66
e) 45
15) Find the ratio between the pizzas sold in B to the
veg pizzas sold in C.

a) 1: 2
b) 20: 9
c) 3: 4
d) 9: 20
e) 3: 16


Directions (Q. 6 - 10) In the following questions, two
equations I and II are given. You have to solve both
the equations and give Answer as,

a) If x > y
b) If x ≥ y
c) If x < y
d) If x ≤ y
e) If x = y or the relation cannot be established

6)
I)X² – 10x – 56 = 0
II) y² + 27y + 72 = 0

7) I) 2x² + 15x + 22 = 0
    II) 3y² – 2y – 16 = 0

8) I)X² + 17x + 52 = 0
    II)Y² + 8y – 48 = 0

9) I) 2x² – 17x + 33 = 0
    II) 3y² + y – 52 = 0

10) I)X² + (125)1/3 = 21
      II) y = ∜256


SOLUTIONS

Directions (1 - 5):
Pizzas sold in C = 108
Veg pizzas in C = 108/12 * 7 = 63
Non- veg pizzas in C = 108/ 12 * 5 = 45
Pizzas sold in A and B = 376 – 108 = 268
Veg : Non-veg pizzas sold by A = 9: 7 (9y, 7y)
Veg : Non-veg pizzas sold by B = 3: 4 (3x, 4x)
Veg pizzas sold by A = 120% Veg pizzas sold by B
=> 6: 5 (6z, 5z)
=> 9y/6z * 5z = 7.5 y
=> 7.5y/3 * 4 = 10y
Veg A: non-veg A: Veg B: non-veg B
9: 7: 7.5: 10
=> 18: 14: 15: 20
=> 268 = 67y
=> y = 4
Veg pizzas in A = 18 * 4 = 72
Non- veg pizzas in A = 14 * 4 = 56
Veg pizzas in B = 15 * 4 =60
Non- veg pizzas in B = 20 * 4 = 80
Total veg Non- veg
A 128 72 56
B 140 60 80
C 108 63
1) Answer: A
Required ratio = 72: 63 = 8: 7
2) Answer: E
Required sum = 56 + 80 + 45 = 181
3) Answer: C
Required % = 60/80 *100 = 75%
4) Answer: D
Required average = (72 + 60) /2 = 66
5) Answer: B
Required ratio = (60 + 80): 63 = 20: 9

6) Answer: E
Explanation:
I)
X² – 10x – 56 = 0
(x – 14) (x + 4) = 0
x = 14, -4
II)
Y² + 27y + 72 = 0
(y + 24) (y + 3) = 0
y = -24, -3
Can’t be determined
7) Answer: D
Explanation:
I) 2x² + 15x + 22 = 0
2x² + 4x + 11x + 22 = 0
2x(x + 2) + 11(x + 2) = 0
(2x + 11) (x + 2) = 0
x = -11/2, -2 = -5.5, -2
II) 3y² – 2y – 16 = 0
3y² + 6y – 8y – 16 = 0
3y(y + 2) – 8 (y + 2) = 0
(3y – 8) (y + 2) = 0
Y = 8/3, -2
x ≤ y
8) Answer: E
Explanation:
I)
X² + 17x + 52 = 0
(x + 13) (x + 4) = 0
x = -13, -4
II)
Y² + 8y – 48 = 0
(y + 12) (y – 4) = 0
y = -12, 4
Can’t be determined
9) Answer: e)
Explanation:
I) 2x² – 17x + 33 = 0
2x² – 6x – 11x + 33 = 0
2x (x – 3) – 11 (x – 3) = 0
(2x – 11) (x – 3) = 0
x = 5.5, 3
II) 3y² + y – 52 = 0
3y² – 12y + 13y – 52 = 0
3y (y – 4) + 13 (y – 4) = 0
(3y + 13) (y – 4) = 0
y = -13/3, 4 = - 4.33, 4
Can’t be determined
10) Answer: D
Explanation:
I)
X² + (125)1/3 = 21

X² + (5³)¹/³ = 21

X² = 21 – 5
x = (16)1/2 = 4, -4
II) y = ∜256
y = 4
x ≤ y