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Direction (1-5): Study the line graph carefully and answer the given questions. The graph shows the total number of students in different colleges and the number of difference between boys and girls in 2017.
Note:
1. The total number of students in each college=Total number of boys + Total number of girls
2. In each college the number of boys is greater than the number of girls.

1. The total number of boys from college A and college C together is what percentage more than that of the total number of girls from college D and college F together?

A. 122.50% B. 175% C. 206.25% D. 125.75% E. 185%

2. What is the average number of girls in college B, college C and college D together?

A. 220 B. 180 C. 200 D. 210 E. 170

3. If in 2018, the total number of students from college D increased by 30% and the total number of girls from college D in 2018 is equal to the total number of girls from college C in 2017. Then find the difference between the total number of boys from college D in 2018 to that of the total number of boys from college C in 2017.

A. 40 B. 70 C. 80 D. 50 E. 60

4. If in college B, the ratio of the total number of students passed to failed is 4:1. If the total number of boys failed is ”X” and the total number of girls failed is “4X”. Then find the ratio of the total number of boys passed to the total number of girls passed from that college?

A. 5:2 B. 3:1 C. 4:3 D. 2:3 E. 5:1

5. The total number of boys from college B and college E together is approximately what percentage more/less than that of the total number of boys from college D and college F together?

A. 18% B. 21% C. 9% D. 14% E. 23%

6. Ritu invested her total saving in three different FD schemes A, B and C in the ratio of 5 : 4 : 6 on CI for two years at the rate of 10%, 15% and 20% respectively. If interest is calculated annually and interest from scheme B is Rs. 744 more than interest from scheme A then, find difference between interest received from scheme C and scheme B by Ritu ?

(a) Rs. 4185 (b) Rs. 4175 (c) Rs. 3840
(d) Rs. 4580 (e) Rs. 3250

7. A bank offers 10% p.a. at CI in scheme ‘A’, 20% p.a. at CI in scheme ‘B’ and 40% p.a. at CI in scheme ‘C’. Veer have same amount in his hand. He invested 32% amount in scheme ‘A’, 20% in scheme ‘B’ and remaining in scheme ‘C’. After two year he received 6600 as interest. Find the difference between amount invested by Veer on scheme ‘C’ to that of in scheme ‘B’.
(a) 5,000 (b) 4,000 (c) 2,000
(d) 3,000 (e) 2,500

1. Ans. C.
In college A, Total number of students=700 Difference between boys and girls=420 As we know in each college the number of boys is greater than the number of girls. Let the number of girls=x Let the number of boys= x+420 So, x + x + 420=700 2x=700-420 x=140
So, total number of girls=140 Total number of boys=140+420=560 Now this way we can get this table,

The total number of boys from college A and college C together=560+420=980 The total number of girls from college D and college F together= 200+120=320 So, required percentage=(980-320)/320 ×100 = 660/320 × 100 =206.25%
2. Ans. A.
In college A, Total number of students=700 Difference between boys and girls=420 As we know in each college the number of boys is greater than the number of girls. Let the number of girls=x Let the number of boys= x+420 So, x + x + 420=700 2x=700-420 x=140 So, total number of girls=140 Total number of boys=140+420=560 Now this way we can get this table,

The total number of girls in college B, college C and college D together=180+280+200=660 So, required average=660/3=220
3. Ans. D.
In college A, Total number of students=700 Difference between boys and girls=420 As we know in each college the number of boys is greater than the number of girls. Let the number of girls=x Let the number of boys= x+420
So, x + x + 420=700 2x=700-420 x=140 So, total number of girls=140 Total number of boys=140+420=560 Now this way we can get this table,

The total number of students from college D in 2018 = 500/100 ×130=650 The total number of girls from college C in 2017=280 The total number of girls from college D in 2018=280 The total number of boys from college D in 2018=650-280=370 The total number of boys from college C in 2017=420 So, required difference=420-370=50
4. Ans. B.
In college A, Total number of students=700 Difference between boys and girls=420 As we know in each college the number of boys is greater than the number of girls. Let the number of girls=x Let the number of boys= x+420
So, x + x + 420=700 2x=700-420 x=140 So, total number of girls=140 Total number of boys=140+420=560 Now this way we can get this table,

The total number of students in college B=500 The total number of boys in college B=320 The total number of girls in college B=180 The total number of students passed= 500/(4+1) ×4= 400 The total number of students failed=500-400=100 The total number of boys failed=X The total number of girls failed=4X So, X+4X=100 5X=100 X=20 So, the total number of boys failed=20 The total number of boys passed=320-20=300 The total number of girls failed=4X=4×20=80 The total number of girls passed=180-80=100 So, required ratio = 300/100 = 3:1
5. Ans. D.
In college A, Total number of students=700 Difference between boys and girls=420 As we know in each college the number of boys is greater than the number of girls. Let the number of girls=x Let the number of boys= x+420 So, x + x + 420=700 2x=700-420 x=140 So, total number of girls=140 Total number of boys=140+420=560 Now this way we can get this table,

The total number of boys from college B and college E together=320+340=660 The total number of boys from college D and college F together=300+280=580 So, required percentage=(660-580)/580 ×100= 80/580 × 100 =14%(Approx)

6. (a); Let total saving of Ritu be x Rs.
Invested in Scheme A = 5𝑥/15
= 𝑥/3 Rs.
Amount Invested in scheme B = 4𝑥/15 Rs. Invested in scheme C = 2𝑥/5𝑅𝑠.
Two year C.I on 10% =10+10+ 10×10/100
= 21%
Two year CI on 15% =15+15 +15×15/100
= 32.25 %
Two year CI on 20% =20+20+ 20×20/100
= 44%
ATQ,
4𝑥/15×32.25/100𝑥/3×21/100=744
129𝑥/150021𝑥/300=744
24x = 744×1500
x = 744×1500/24
x = 46500 Rs.
Required difference
= 46500×6/15×44/10046500×4/15×32.25/100= 8184 – 3999
= 4185 Rs.
7.