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**Direction (1-5):**

*Study the line graph carefully and answer the given questions. The graph shows the total number of students in different colleges and the number of difference between boys and girls in 2017.*

Note:

1. The total
number of students in each college=Total number of boys + Total number of girls

2. In each
college the number of boys is greater than the number of girls.

1. The total
number of boys from college A and college C together is what percentage more
than that of the total number of girls from college D and college F together?

A. 122.50% B.
175% C. 206.25% D. 125.75% E. 185%

2. What is the
average number of girls in college B, college C and college D together?

A. 220 B. 180
C. 200 D. 210 E. 170

3. If in 2018,
the total number of students from college D increased by 30% and the total
number of girls from college D in 2018 is equal to the total number of girls
from college C in 2017. Then find the difference between the total number of
boys from college D in 2018 to that of the total number of boys from college C
in 2017.

A. 40 B. 70 C.
80 D. 50 E. 60

4. If in
college B, the ratio of the total number of students passed to failed is 4:1.
If the total number of boys failed is ”X” and the total number of girls failed
is “4X”. Then find the ratio of the total number of boys passed to the total
number of girls passed from that college?

A. 5:2 B. 3:1
C. 4:3 D. 2:3 E. 5:1

5. The total
number of boys from college B and college E together is approximately what
percentage more/less than that of the total number of boys from college D and
college F together?

A. 18% B.
21% C. 9% D. 14% E. 23%

6.
Ritu invested her total saving in three different FD schemes A, B and C in the
ratio of 5 : 4 : 6 on CI for two years at the rate of 10%, 15% and 20%
respectively. If interest is calculated annually and interest from scheme B is
Rs. 744 more than interest from scheme A then, find difference between interest
received from scheme C and scheme B by Ritu ?

(a)
Rs. 4185 (b) Rs. 4175 (c) Rs. 3840

(d) Rs. 4580 (e)
Rs. 3250

7. A bank offers 10% p.a. at CI in scheme ‘A’,
20% p.a. at CI in scheme ‘B’ and 40% p.a. at CI in scheme ‘C’. Veer have same
amount in his hand. He invested 32% amount in scheme ‘A’, 20% in scheme ‘B’ and
remaining in scheme ‘C’. After two year he received 6600 as interest. Find the
difference between amount invested by Veer on scheme ‘C’ to that of in scheme
‘B’.

(a)
5,000 (b) 4,000 (c) 2,000

(d) 3,000 (e) 2,500

**ANSWERS**

1. Ans. C.

In college
A, Total number of students=700 Difference between boys and girls=420 As we
know in each college the number of boys is greater than the number of girls.
Let the number of girls=x Let the number of boys= x+420 So, x + x + 420=700
2x=700-420 x=140

So, total
number of girls=140 Total number of boys=140+420=560 Now this way we can get
this table,

The total number of boys from
college A and college C together=560+420=980 The total number of girls from
college D and college F together= 200+120=320 So, required percentage=(980-320)/320
×100 = 660/320 × 100 =206.25%

2. Ans. A.

In college
A, Total number of students=700 Difference between boys and girls=420 As we
know in each college the number of boys is greater than the number of girls.
Let the number of girls=x Let the number of boys= x+420 So, x + x + 420=700
2x=700-420 x=140 So, total number of girls=140 Total number of boys=140+420=560
Now this way we can get this table,

The total number of girls in
college B, college C and college D together=180+280+200=660 So, required
average=660/3=220

3. Ans. D.

In college
A, Total number of students=700 Difference between boys and girls=420 As we
know in each college the number of boys is greater than the number of girls.
Let the number of girls=x Let the number of boys= x+420

So, x + x + 420=700 2x=700-420 x=140 So, total
number of girls=140 Total number of boys=140+420=560 Now this way we can get
this table,

The total number of students
from college D in 2018 = 500/100 ×130=

**650**The total number of girls from college C in 2017=280 The total number of girls from college D in 2018=**280**The total number of boys from college D in 2018=650-280=370 The total number of boys from college C in 2017=420 So, required difference=420-370=50
4. Ans. B.

In college
A, Total number of students=700 Difference between boys and girls=420 As we
know in each college the number of boys is greater than the number of girls.
Let the number of girls=x Let the number of boys= x+420

So, x + x + 420=700 2x=700-420 x=140 So, total
number of girls=140 Total number of boys=140+420=560 Now this way we can get
this table,

The total number of students in
college B=500 The total number of boys in college B=

**320**The total number of girls in college B=**180**The total number of students passed= 500/(4+1) ×4= 400 The total number of students failed=500-400=100 The total number of boys failed=X The total number of girls failed=4X So, X+4X=100 5X=100 X=20 So, the total number of boys failed=**20**The total number of boys passed=320-20=300 The total number of girls failed=4X=4×20=**80**The total number of girls passed=180-80=100 So, required ratio = 300/100 = 3:1
5. Ans. D.

In college
A, Total number of students=700 Difference between boys and girls=420 As we
know in each college the number of boys is greater than the number of girls.
Let the number of girls=x Let the number of boys= x+420 So, x + x + 420=700
2x=700-420 x=140 So, total number of girls=140 Total number of boys=140+420=560
Now this way we can get this table,

The total
number of boys from college B and college E together=320+340=660 The total
number of boys from college D and college F together=300+280=580 So, required
percentage=(660-580)/580 ×100= 80/580 × 100 =14%

**(Approx)**

**6.**

**(a);**Let total saving of Ritu be x Rs.

Invested
in Scheme A = 5𝑥/15

=
𝑥/3 Rs.

Amount
Invested in scheme B = 4𝑥/15 Rs. Invested in scheme C = 2𝑥/5𝑅𝑠.

Two
year C.I on 10% =10+10+ 10×10/100

=
21%

Two
year CI on 15% =15+15 +15×15/100

=
32.25 %

Two
year CI on 20% =20+20+ 20×20/100

=
44%

ATQ,

4𝑥/15×32.25/100−𝑥/3×21/100=744

129𝑥/1500−21𝑥/300=744

24x
= 744×1500

x
= 744×1500/24

x
= 46500 Rs.

Required
difference

= 46500×6/15×44/100−46500×4/15×32.25/100= 8184 – 3999

=
4185 Rs.

**7.**