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Direction: (15) A number is wrong in the following number series. Select the wrong number.
Q1. 75,
76, 156,475, 1924, 9645
(a)
75
(b)
475
(c)
1924
(d)
9645
(e)
156
Q2.
23, 35, 32, 46, 41, 55
(a)
35
(b)
32
(c)
23
(d)
46
(e)
41
Q3.
60, 61,64, 79, 185, 1129
(a)
185
(b)
61
(c)
60
(d)
1129
(e)
79
Q4.
74 , 417 , 633, 756 , 822 , 849
(a)
74
(b)
756
(c)
849
(d)
633
(e)
NoT
Q5.
6, 16, 42, 110, 274, 690
(a)
6
(b)
110
(c)
274
(d)
42
(e)
690
Q6. A man sells 3 article P, Q and R for Rs.
5200 each. He earns profit of 1623% on article P,
and he sells article Q at the loss of 1427% but in the
whole transaction there is no profit and no loss. find out the profit
percentage of the article R?
(a)
50/21%
(b)
100/41%
(c)
100/31%
(d)
100/7%
(e)
100/39%
Q7.
Shivam sells sweets at Rs 72 per kg which is made up of flour and sugar in the
ratio of 5 : 3. The ratio of price of flour and price of sugar is 3 : 7 in one
kg and he made a profit of 33 1/3% on selling 1kg
sweets. What is the cost price of sugar?
(a)
Rs 72 per kg
(b)
Rs 80 per kg
(c)
Rs 90 per kg
(d)
Rs 84 per kg
(e)
None of these.
Q8.
A shopkeeper marks up price of an article ‘3X’% above its cost price and
difference between marked price & cost price is Rs. 360. Shopkeeper allows
‘X’ % discount and difference between marked price and selling price is Rs.
156, find the overall profit of shopkeeper on selling the article?
(a)
Rs. 184
(b)
Rs. 204
(c)
Rs. 324
(d)
Rs. 285
(e)
Rs. 384
Q9.
If the digits of a two digits number are reversed then the number so obtained
becomes 3/8th times of original number. Then find sum of square of digits of
the number.
(a)
48
(b)
51
(c)
53
(d)
56
(e)
62
Q10.
A sold an article to B at 20% profit. B then sold it to C at 25% profit and
then C sold it to D for Rs. 2210 and thus earning same amount of loss that A
has earned as profit. Then, find the loss percentage of C.
(a)
40/3%
(b)
41/3%
(c)
40/7%
(d)
30/7%
(e)
31/3%
Solutions:
S1.
ANS B
Sol:
The series is
75*1+ 1^{2}= 76
76*2 + 2^{2}= 156
156*3+ 3^{2}= 477
hence 475 is wrong term
75*1+ 1^{2}= 76
76*2 + 2^{2}= 156
156*3+ 3^{2}= 477
hence 475 is wrong term
S2.
ANS A
The pattern of the series is:
S3.
ANSA
The pattern of the series is:
S4.
ANS B
The series is
74+ 7^{3}= 417
417+ 6^{3}= 633
633 + 5^{3}= 758
So, 756 is the wrong number in the series.
74+ 7^{3}= 417
417+ 6^{3}= 633
633 + 5^{3}= 758
So, 756 is the wrong number in the series.
S5.
Ans. (b)
6×2.5+1=15+1=16
16×2.5+2=40+2=42
42×2.5+3=105+3=108
108×2.5+4=270+4=274
274×2.5+5=685+5=690
16×2.5+2=40+2=42
42×2.5+3=105+3=108
108×2.5+4=270+4=274
274×2.5+5=685+5=690
S6. Ans. (b)
Sol.
Let selling price of each
article is Rs. 42x
So, selling price of all three
article is Rs.126x
So, cost price of all three
article is also Rs. 126x
Cost price of article P = 67×42=𝑅𝑠 36𝑥
Cost price of article Q = 76×42=𝑅𝑠 49𝑥
So, cost price of article R =
[126−36−49]x
Cost price of article R = Rs.
41x
So, profit %= (42−41)/41 ×100
= 100/41%
S2. Ans.(e)
Sol.
CP of sweet per kg = 72×34
= Rs 54 per kg
Price of sugar in sweet = 54×710
Hence, cost price of 1 kg of
sugar = 54×710×83
= Rs.100.8
S3. Ans.(b)
S4. Ans.(c)
Sol. Let the digit at tens
place & units place be ‘x’ & ‘y’ respectively
So, original Number = 10 × x +
y
Resultant Number = 10 × y + x
ATQ,
3/8×(10 × x + y) =(10×y + x)
22x=77y
x/y=7/2
Since number is 2 digits so,
only one possible case in this case
Original number =72
And reversed number =27
Required sum
= 49+4=53
S5. Ans.(a)
Sol.
Let C.P. of an article for A be
Rs x
So, Persons

CP

SP

A

X

1.2x

B

1.2x

1.5x

C

1.5x

Rs. 2210

ATQ,
1.2x – x = 1.5x – 2210
0.2x = 1.5x – 2210
1.3x = 2210
x = Rs 1700
Required % =(1700×20/100) ÷ (150/100×1700)×100
=13 1/3%