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**Directions (1**

**– 5): Study the following information carefully and answer the questions give below:**

**The bar graph 1 shows the time taken by five pipes (A, B, C, D and E) to fill a tank**

**The bar graph 2 shows the time taken by five pipes (P, Q, R, S and T) to empty the tank**

The following table shows the ratio of time taken by pipes to fill the tank.

**1) Pipe A and Pipe B opened simultaneously for 4 minutes, then closed and then pipe F and pipe Q are opened for 2 minutes, and then closed. Find the time taken by pipe G to fill the remaining part of the tank.**

a) 7 minutes

b) 139/36
minutes

c) 5 minutes

d) 178/39
minutes

e) None of
these

**2) Efficiency of pipe K is twice the efficiency of pipe A and efficiency of pipe L is 1.5 times the efficiency of pipe S. Pipe C and pipe K are opened simultaneously for 3 minutes and then closed. Find the time taken by pipe L and pipe R together to empty the filled part of the tank.**

a) 4 minutes

b) 47/12
minutes

c) 32/5
minutes

d) 5 minutes

e) None of
these

a) 67.67%

**3) Time taken by pipe M to fill the tank is 20% more than the time taken by pipe I to fill the tank and efficiency of pipe N is twice the efficiency of pipe J. Time taken by pipe M and pipe N to fill the tank is what percent of the time taken by pipe D and pipe E together to fill the tank.**a) 67.67%

b) 74.44%

c) 98.48%

d) 81.14%

e) 83.33%

**4) Find the respective ratio of time taken by pipe B, pipe G and pipe P together to fill the tank to that of time taken by pipe E, pipe H and pipe S together to fill the tank.**

a) 4:5

b) 5:6

c) 6:7

d) 3:4

e) None of
these

**5) Pipe A, pipe C and pipe E are opened simultaneously for 4 minutes then closed and pipe P and pipe S are opened for 2 minutes then closed. Find the time taken by pipe G and pipe J to fill the remaining part of the tank.**

a) 27/13 days

b) 41/27 days

c) 31/11 days

d) 51/29 days

e)
None of these**Answers :**

**Direction (1-5):**

**1) Answer: b)**

Part of the
tank filled by pipe A in one minute = 1/12

Part of the
tank filled by pipe B in one minute = 1/15

Time taken by
pipe F to fill the tank = 4/3 x 12 = 16 minutes

Part of the
tank filled by pipe F in one minute = 1/16

Time taken by
pipe G to fill the tank = 2/3 x 15 = 10 minutes

Part of the
tank filled by pipe G in one minute = 1/10

Part of the
tank emptied by pipe Q in one minute = 1/18

Let required
time = t minutes

According to
the question

4/15 + 4/12 +
2/16 – 2/18 + t/10 = 1

=> t/10 = 1
– 4/15 – 1/3 – 1/8 + 1/9

=> t/10 =
(360 – 120 – 90 – 45 + 40)/360

=> t/10 =
139/360

=> t =
139/360 x 10

=> t =
139/36 minutes

**2) Answer: c)**

Part of the
tank filled by pipe A in one minute = 1/12

Part of the tank filled by
pipe K in one minute = 2/12 = 1/6

Part of the tank filled by
pipe C in one minute = 1/10

Part of the tank emptied by
pipe S in one minute = 1/24

Part of the tank emptied by
pipe L in one minute = 1.5/24 = 1/16

Part of the tank emptied by
pipe R in one minute = 1/16

Part of the tank filled by
pipe C and pipe K in 3 minutes = 3/10 + 3/6

= (9 + 15)/30

= 24/30

Let the required time taken =
t minutes

t/16 + t/16 = 24/30

=> 2t/16 = 24/30

=> t = 24/30 x 16/2

=> t = 32/5 minutes

**3) Answer: c)**

Time taken by
pipe I to fill the tank = 5/4 x 8 = 10 minutes

Part of the
tank filled by pipe I in one minute = 1/10

Time taken by
pipe M to fill the tank = 10 x 120/100 = 12 minutes

Part of the
tank filled by pipe M in one minute = 1/12

Time taken by
pipe J to fill the tank = 10/9 x 18 = 20 minutes

Part of the
tank filled by pipe J in one minute = 1/20

Part of the
tank filled by pipe N in one minute = 2/20 = 1/10

Part of the
tank filled by pipe D in one minute = 1/8

Part of the
tank filled by pipe E in one minute = 1/18

Let the time
taken by pipe M and pipe N to fill the tank = t minutes

And the time
taken by pipe D and pipe E to fill the tank = k minutes

t/12 + t/10 =
1

=> (5t +
6t)/60 = 1

=> 11t/60 =
1

=> t = 60/11 minutes

And

k/8 + k/18 = 1

(9k + 4k)/72 = 1

=> k = 72/13 minutes

Required percentage =
(60/11)/(72/13) x 100

= 60/11 x 13/72 x 100

= 98.48%

**4) Answer: b)**

Part of the
tank filled by pipe B in one minute = 1/15

Time taken by
pipe G to fill the tank = 2/3 x 15 = 10 minutes

Part of the
tank filled by pipe G in one minute = 1/10

Part of the
tank emptied by pipe P in one minute = 1/20

Part of the
tank filled by pipe E in one minute = 1/18

Time taken by
pipe H to fill the tank = 6/5 x 10 = 12 minutes

Part of the
tank filled by pipe H in one minute = 1/12

Part of the
tank emptied by pipe S in one minute = 1/24

Let the time
taken by pipe B, pipe g and pipe P together to fill the tank = t minutes

And the time
taken by pipe E, pipe H and pipe S together to fill the tank = k minutes

t/15 + t/10 –
t/20 = 1

=> (4t + 6t
– 3t)/60 = 1

=> 7t/60 =
1

=> t = 60/7
minutes

And

k/18 + k/12 –
k/24 = 1

=> (4k + 6k
– 3k)/72 = 1

=> 7k/72 =
1

=> k = 72/7
minutes

Required ratio = 60/7: 72/7 =
5:6

**5) Answer: b)**

Part of the
tank filled by pipe A in one minute = 1/12

Part of the
tank filled by pipe C in one minute = 1/10

Part of the
tank filled by pipe E in one minute = 1/18

Part of the
tank emptied by pipe P in one minute = 1/20

Part of the
tank emptied by pipe S in one minute = 1/24

Time taken by
pipe G to fill the tank = 2/3 x 15 = 10 minutes

Part of the
tank filled by pipe G in one minute = 1/10

Time taken by
pipe J to fill the tank = 10/9 x 18 = 20 minutes

Part of the
tank filled by pipe J in one minute = 1/20

Let the
required time taken = t minutes

4/12 + 4/10 +
4/18 – 2/20 – 2/24 + t/10 + t/20 = 1

=>1/3 + 2/5
+ 2/9 – 1/10 – 1/12 + (2t + t)/20 = 1

=> (60 + 72
+ 40 – 18 – 15)/180 + 3t/20 = 1

=> 139/180
+ 3t/20 = 1

=> 3t/20 =
1 – 139/180

=> 3t/20 =
(180 – 139)/180

=> 3t/20 =
41/180

=> t =
41/180 x 20/3

=> t =
41/27 days