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Directions (1 – 5): Study the following information
carefully and answer the questions give below:
The bar
graph 1 shows the time taken by five pipes (A, B, C, D and E) to fill a tank
The bar graph 2 shows the time taken by five pipes (P, Q, R, S and T) to empty the tank
The following table shows the ratio of time taken by pipes to fill the tank.
1) Pipe A and Pipe B opened
simultaneously for 4 minutes, then closed and then pipe F and pipe Q are opened
for 2 minutes, and then closed. Find the time taken by pipe G to fill the
remaining part of the tank.
a) 7 minutes
b) 139/36
minutes
c) 5 minutes
d) 178/39
minutes
e) None of
these
2)
Efficiency of pipe K is twice the efficiency of pipe A and efficiency of pipe L
is 1.5 times the efficiency of pipe S. Pipe C and pipe K are opened simultaneously
for 3 minutes and then closed. Find the time taken by pipe L and pipe R
together to empty the filled part of the tank.
a) 4 minutes
b) 47/12
minutes
c) 32/5
minutes
d) 5 minutes
e) None of
these 3) Time taken by
pipe M to fill the tank is 20% more than the time taken by pipe I to fill the
tank and efficiency of pipe N is twice the efficiency of pipe J. Time taken by
pipe M and pipe N to fill the tank is what percent of the time taken by pipe D
and pipe E together to fill the tank.
a) 67.67%
a) 67.67%
b) 74.44%
c) 98.48%
d) 81.14%
e) 83.33%
4) Find the
respective ratio of time taken by pipe B, pipe G and pipe P together to fill
the tank to that of time taken by pipe E, pipe H and pipe S together to fill
the tank.
a) 4:5
b) 5:6
c) 6:7
d) 3:4
e) None of
these
5) Pipe A,
pipe C and pipe E are opened simultaneously for 4 minutes then closed and pipe
P and pipe S are opened for 2 minutes then closed. Find the time taken by pipe
G and pipe J to fill the remaining part of the tank.
a) 27/13 days
b) 41/27 days
c) 31/11 days
d) 51/29 days
e)
None of these
Answers :
Direction (1-5):
1) Answer: b)
Part of the
tank filled by pipe A in one minute = 1/12
Part of the
tank filled by pipe B in one minute = 1/15
Time taken by
pipe F to fill the tank = 4/3 x 12 = 16 minutes
Part of the
tank filled by pipe F in one minute = 1/16
Time taken by
pipe G to fill the tank = 2/3 x 15 = 10 minutes
Part of the
tank filled by pipe G in one minute = 1/10
Part of the
tank emptied by pipe Q in one minute = 1/18
Let required
time = t minutes
According to
the question
4/15 + 4/12 +
2/16 – 2/18 + t/10 = 1
=> t/10 = 1
– 4/15 – 1/3 – 1/8 + 1/9
=> t/10 =
(360 – 120 – 90 – 45 + 40)/360
=> t/10 =
139/360
=> t =
139/360 x 10
=> t =
139/36 minutes
2) Answer:
c)
Part of the
tank filled by pipe A in one minute = 1/12
Part of the tank filled by
pipe K in one minute = 2/12 = 1/6
Part of the tank filled by
pipe C in one minute = 1/10
Part of the tank emptied by
pipe S in one minute = 1/24
Part of the tank emptied by
pipe L in one minute = 1.5/24 = 1/16
Part of the tank emptied by
pipe R in one minute = 1/16
Part of the tank filled by
pipe C and pipe K in 3 minutes = 3/10 + 3/6
= (9 + 15)/30
= 24/30
Let the required time taken =
t minutes
t/16 + t/16 = 24/30
=> 2t/16 = 24/30
=> t = 24/30 x 16/2
=> t = 32/5 minutes
3) Answer: c)
Time taken by
pipe I to fill the tank = 5/4 x 8 = 10 minutes
Part of the
tank filled by pipe I in one minute = 1/10
Time taken by
pipe M to fill the tank = 10 x 120/100 = 12 minutes
Part of the
tank filled by pipe M in one minute = 1/12
Time taken by
pipe J to fill the tank = 10/9 x 18 = 20 minutes
Part of the
tank filled by pipe J in one minute = 1/20
Part of the
tank filled by pipe N in one minute = 2/20 = 1/10
Part of the
tank filled by pipe D in one minute = 1/8
Part of the
tank filled by pipe E in one minute = 1/18
Let the time
taken by pipe M and pipe N to fill the tank = t minutes
And the time
taken by pipe D and pipe E to fill the tank = k minutes
t/12 + t/10 =
1
=> (5t +
6t)/60 = 1
=> 11t/60 =
1
=> t = 60/11 minutes
And
k/8 + k/18 = 1
(9k + 4k)/72 = 1
=> k = 72/13 minutes
Required percentage =
(60/11)/(72/13) x 100
= 60/11 x 13/72 x 100
= 98.48%
4) Answer: b)
Part of the
tank filled by pipe B in one minute = 1/15
Time taken by
pipe G to fill the tank = 2/3 x 15 = 10 minutes
Part of the
tank filled by pipe G in one minute = 1/10
Part of the
tank emptied by pipe P in one minute = 1/20
Part of the
tank filled by pipe E in one minute = 1/18
Time taken by
pipe H to fill the tank = 6/5 x 10 = 12 minutes
Part of the
tank filled by pipe H in one minute = 1/12
Part of the
tank emptied by pipe S in one minute = 1/24
Let the time
taken by pipe B, pipe g and pipe P together to fill the tank = t minutes
And the time
taken by pipe E, pipe H and pipe S together to fill the tank = k minutes
t/15 + t/10 –
t/20 = 1
=> (4t + 6t
– 3t)/60 = 1
=> 7t/60 =
1
=> t = 60/7
minutes
And
k/18 + k/12 –
k/24 = 1
=> (4k + 6k
– 3k)/72 = 1
=> 7k/72 =
1
=> k = 72/7
minutes
Required ratio = 60/7: 72/7 =
5:6
5) Answer:
b)
Part of the
tank filled by pipe A in one minute = 1/12
Part of the
tank filled by pipe C in one minute = 1/10
Part of the
tank filled by pipe E in one minute = 1/18
Part of the
tank emptied by pipe P in one minute = 1/20
Part of the
tank emptied by pipe S in one minute = 1/24
Time taken by
pipe G to fill the tank = 2/3 x 15 = 10 minutes
Part of the
tank filled by pipe G in one minute = 1/10
Time taken by
pipe J to fill the tank = 10/9 x 18 = 20 minutes
Part of the
tank filled by pipe J in one minute = 1/20
Let the
required time taken = t minutes
4/12 + 4/10 +
4/18 – 2/20 – 2/24 + t/10 + t/20 = 1
=>1/3 + 2/5
+ 2/9 – 1/10 – 1/12 + (2t + t)/20 = 1
=> (60 + 72
+ 40 – 18 – 15)/180 + 3t/20 = 1
=> 139/180
+ 3t/20 = 1
=> 3t/20 =
1 – 139/180
=> 3t/20 =
(180 – 139)/180
=> 3t/20 =
41/180
=> t =
41/180 x 20/3
=> t =
41/27 days
